2000 Watt Pure Sine Wave Inverter 24V
This high efficiency DC-AC inverter converts 24 Volts DC to 2000 Watts of pure sine-wave AC power at 120 Volts, 60 Hz. Features include overload
The maximum amps (current) drawn by a 2000 watts inverter depends on its conversion efficiency and voltage rating of the battery bank. A 2000-watt power inverter running on a battery bank of 12V would draw around 240 amps and with a 24V battery bank, 120 amps could be drawn. However, a battery bank with a 48V would not exceed 60 amps.
A 24V inverter requires a 24V battery, but you can get away with using 3 x 100ah 12V batteries. You just have to wire the batteries in a series to add their voltages together. But if you can get a 24V battery that is just as good.
To calculate the DC current draw from an inverter, use the following formula: Inverter Current = Power ÷ Voltage Where: If you're working with kilowatts (kW), convert it to watts before calculation: Inverter Current = 1000 ÷ 12 = 83.33 Amps So, the inverter draws 83.33 amps from a 12V battery. Inverter Current = 3000 ÷ 24 = 125 Amps
So, the inverter draws 83.33 amps from a 12V battery. Inverter Current = 3000 ÷ 24 = 125 Amps So, a 3000W inverter on a 24V system pulls 125 amps from the battery. Inverter Current = 5000 ÷ 48 = 104.17 Amps The current drawn is approximately 104.17 amps. Understanding how much current your inverter draws is vital for several reasons:
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